36x^2-47=0

Solution for 36x^2-47=0 equation:

36x^2-47=0

a = 36; b = 0; c = -47;
Δ = b2-4ac
Δ = 02-4·36·(-47)
Δ = 6768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6768}=\sqrt{144*47}=\sqrt{144}*\sqrt{47}=12\sqrt{47}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{47}}{2*36}=\frac{0-12\sqrt{47}}{72}
=-\frac{12\sqrt{47}}{72}
=-\frac{\sqrt{47}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{47}}{2*36}=\frac{0+12\sqrt{47}}{72}
=\frac{12\sqrt{47}}{72}
=\frac{\sqrt{47}}{6}
$